Question

a body is thrown with a velocity of 10m/s at an angle of 45 with the horizontal find total time taken​

Answer 1

Answer:

1.44 sec

Explanation:

$t = \frac{2u \sin( \alpha ) }{g} \\ = \frac{2 \times 10 \times \sin(45) }{9.81} \\ = 1.44sec$