Question

A body is thrown with velocity (4i+3j)m/s.Its maximum height

Answer 1

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Answer 2

Answer:

The maximum height of the body is 0.45m.

Explanation:

The maximum height of the body is given as,

$H=\frac{u^2_y}{2g}$        (1)

Where,

H=maximum height attained by the body

uy=velocity along y-axis

g=acceleration due to gravity=10m/s²

From the question we have,

$v=4\hat{i}+3\hat{j}m/s$       (2)

The velocity of the body along the x-axis(ux)=4m/s

The velocity of the body along the y-axis(uy)=3m/s

By substituting the value of uy and g in equation (1) we get;

$H=\frac{(3)^2}{2\times 10}=\frac{9}{20}=0.45m$

Hence, the maximum height of the body is 0.45m.