Physics, asked by KrishanBudania9997, 8 months ago

A body is travelling with a velocity 30m/s . It is given an acceleration 5m/s . What will be its velocity after 4s

Answers

Answered by Anonymous
73

Given :

➳ Initial velocity = 30m/s

➳ Acceleration = 5m/s²

➳ Time interval = 4s

To Find :

➠ Final velocity of body after the given interval of time.

Solution :

➝ Acceleration is defined as the rate of change in velocity.

➝ It is a vector quantity having both magnitude as well as direction.

➝ It can be positive, negative or zero.

➝ SI unit : m/s²

First equation of kinematics :

⇒ a = (v - u) / t

⇒ v = u + at

⇒ v = 30 + (5 × 4)

⇒ v = 30 + 20

v = 50m/s


Anonymous: Awesome ^•^
Anonymous: Thankuuh Thug :)
Answered by Anonymous
66

\sf\Large{\underbrace{\red{Answer \implies 50\:m/s}}}

\sf\large{\underline{\underline{Given:}}}

\sf{ Initial \:velocity\:(v) = 30\:m/s}

\sf{Acceleration\: (a)  = 5\:m/{s}^{2}}

\sf\large{\underline{\underline{To \:Find:}}}

\sf{Velocity\:after\:4\:s\:(Final\:Velocity..ie. u) =...... ?}

\sf\large{\underline{\underline{SolUTiOn:}}}

\sf{To\:find \:the\:velocity\:after\:4\:sec\:we\:use\:the}\sf{first\:equation\:of\:motion...i.e.}

\sf{\red{\implies  v = u + at}}

\sf{\green{\implies v = 30 + 5 \times 4}}

\sf{\orange{\implies v = 50\:m/s}}

\sf\large{\underline{\underline{Hence:}}}

\bold{\fbox{\color{red}{ \: \: \: Velocity\:after\:4\:seconds = 50\:m/s}}}


Anonymous: nice work :)
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