A body is whirled in a horizontal circle of radius 20.cm . It has an angular velocity of 110 rad/s. What is the linear velocity at any point on circular path ?
Answers
Answered by
0
Answer:
22 m/s
Explanation:
Since v= r x ω [r = radius ; ω = Angular velocity]
v = 110 x 0.2 m/s
v = 22 m/s
Answered by
7
Answer:
- The Linear velocity (v) at any instant is 22 m/s.
Given:
- Radius of Circle (r) = 20 cm.
- Angular velocity (ω) = 110 rad/sec.
Explanation:
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From the relation we know,
⇒ v = r ω
Where,
- v Denotes Linear velocity.
- r Denotes radius of circle.
- ω Denotes Angular velocity.
Now, Substituting the values,
⇒ v = 20 cm x 110 rad/sec.
Since radius (r) is given in cm We need to convert into meters.
We know,
⊕ 1 cm = 10⁻³ m
∴ 20 cm = 20 x 10⁻³ m.
∴ 20 cm = 2 x 10⁻² m.
Substituting in the Equation,
⇒ v = 20 x 10⁻² x 110
⇒ v = 0.2 x 110
⇒ v = 2 x 11
⇒ v = 22 m/s.
∴ The Linear velocity (v) at any instant is 22 m/s.
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Additional Formulas:
- d = r x θ
- a = r x α
- v = r x ω
- τ = F x r
- τ = I x α
- I = Σ Mr²
- L = P x r
- L = I x ω
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