Question

a body mass 10 kg initially ay rest acquite velocity 10 ms what is work done

Answer 1

May be work done is 0

Answer 2

Work done = change in kinetic energy
W=
$1 \div 2 \times m( {v}^{2} - {u}^{2} )$
0.5×10×(10×10-0)
5×100
500J

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