Question

A body mass 5kg is acted upon by the two perpendicular forces of 8N & 6N give the magnitude N direction of the acceleration of the body

Answer 1

we have to find the mass of the body,
two forces are given so,

R = √((8^2)+(-6^2))
= √(64+36)
= √(100) = 10N
θ is the angle of R to the force of 8N.

θ = tan-1(-6/8)
θ = -36.87°

The negative sign indicates clockwise direction,and the force of the magnitude is 8N,
So acceleration of the body is ,
F = m*a
F =force,m=mass,a=acceleration,
acceleration, a = F / m

a = 10/5 = 2 m/sec^2.

Therefore result is 2 m/sec^2

Answer 2

For two perpendicular forces
Resultant force = √(F₁² + F₂²)
= √[(8 N)² + (6 N)²]
= √(64 + 36) N
= 10 N

Direction:
Tanθ = 6 N / 8 N = 3 / 4
θ = 37 degrees

Resultant force is at an angle 37 degrees with 8 N (or) 54 degrees with 6 N.