a body move in a square path ABCD and start from a if a = 20m and body take two and the half round find distance and displacement
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Answer:
Distance = Length of path travelled
=AB+BC
=15+9
=24km
Displacement = Shortest path from initial to final position
=AC
=
(AB)
2
+(BC)
2
{Pythagoras Theorem}
=
225+81
=17.5km
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