Physics, asked by Anonymous, 4 hours ago

A body moves 3m towards north, then 6m towards east and finally 3m towards south. Calculate the:
a) distance covered, and
b) displacement of the body. ​

Answers

Answered by YourHelperAdi
55

the body moves 3m north , then 6m east , and 3 m south

a) distance covered = 6+3+3 = 12m

b) displacement = as he returned to the axis of north he started ,so he is now 6 m from his starting place

so his displacement = 6m

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Answered by siddharthapriy72
0

Answer:

Distance = 3+6+3 = 12m

Displacement = 6 m

Explanation:

Refer to the attached image.

Distance is the total path covered by the object or body.

Distance is a scalar quantity that clearly signifies that it has only magnitude and no direction.

So, here distance = 3+6+3 = 12m.

But, displacement is the length between the final and the initial position. It is a vector quantity that shows that it has both magnitudes as well as direction. To be more precise, displacement is the shortest distance between the initial and final positions.

So, here displacement = 6 m.

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