Question

A body moves 6 metre North 8 metre east and 10 metre vertically upward the resultant displacement of body from its initial position is​

Answer 1

Answer:

The resultant displacement of body from its initial position is 14 meters.

Explanation:

Using pythagoras theorm first find the resultant of the first two displacements

$a = \sqrt{( {6)}^{2} + ( {8)}^{2} }$

$a = \sqrt{100 } = 10$

now find the final displacement from this (a=10) and the vertical displacement (which is also 10)

$d = \sqrt{( {10}^{2} + ( {10)}^{2} }$

$d = \sqrt{200} = 14meter$