Question

A Body moves 6m north ,8m east and 10m vertically upwards, what is its result displacement from initialposition.

Answer 1

Answer:

When you travel 6m North and 8m East, in 2 dimensions the resultant vector by Pythagoras theorem is 10m.

From that point it travels 10m upwards which again forms a right angle triangle in a different plan from the resultant vector whose magnitude is also 10m

Therefore again applying Pythagoras theorem, root of 10^2 + 10^2 = 10xsqrt(2)

Answer 2

GIVEN :-

A boy move 6 m north 8 m east and 10 m vertically upwards.

TO FIND :-

The resultant displacement from the initial position.

PRE-REQUISITE :-

Displacement is the shortest length between the initial position and the final position.

OR

Displacement is the change in position vector.

SOLUTION :-

If a body moves 6 m North, 8 m East and 10 m vertically upwards then its resultant displacement from initial position will be in the form of a cuboid with length 6 m,  breadth 8 m and height 10 m.

And the resultant displacement would be the diagonal of this cuboid.

So, the diagonal of a cuboid :-

√(6²+8²+10²)

= √200

= √(100 × 2)

= 10√2

∴ So, the displacement of the boy from his initial position is 10√2 units.