A body moves along a curved path of a quarter circle. what is the ratio of distance to displacement?
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Answered by
129
Distance = πr/2
Displacement = r√2
Distance/ Displacement = πr / (2r√2) = π/(2√2) = (π√2) / 4
Ratio of distance to displacement is π : 2√2 (or) π√2 : 4
Displacement = r√2
Distance/ Displacement = πr / (2r√2) = π/(2√2) = (π√2) / 4
Ratio of distance to displacement is π : 2√2 (or) π√2 : 4
Answered by
193
Given :Body moves in quarter part of circle.So, distance will be quarter of circumference of circle=2πr/4=πr/2Displacement will be shortest distance .From the figure : AB is the Displacement .It forms a right angle traingle.AB² =displacement=Hypotenuse=√(r²+r²)
=√2r²=r√2
Ratio of distance to displacement =πr/2xr√2
=π/2√2
=π/2√2
=22/√2x(2x7)
=11/√2x7
∴ Ratio of Distance to displacement is 11 : √2(7)
=√2r²=r√2
Ratio of distance to displacement =πr/2xr√2
=π/2√2
=π/2√2
=22/√2x(2x7)
=11/√2x7
∴ Ratio of Distance to displacement is 11 : √2(7)
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