Question

.
A body moves along the circular path as shown
in figure. Find magnitude of displacement
between point A & B :-

(1) R/2
(2) R/4
(3) R
(4)2R​

Answer 1

$\huge{\bf{\underline{\red{SOLUTION}}}}$

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Consider $\triangle{BOC}$

BC=Rcos60°

Similarly.

AC= Rsin60°

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Net displacement in x axis

=R-Rcos60

=R(1-cos60)

Net displacement in y axis

=R sin60

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TOTAL DISPLACEMENT

=$\sqrt{x^{2}{+}y^{2}}$

Solving we get

=$\sqrt{2R(1-cos60)}$

=$\sqrt{2R×2sin60÷2}$

=${2Rsin30}$

=2R×(1÷2)

=R

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$\large{\underline{\underline{\red{Answer=R}}}}$

Answer 2

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