A bus is moving along a straight road with a
uniform acceleration of 2 m/s2. If the initial velocity
of the bus is 12 m/s, then what is the distance
covered by it in the 3rd second of motion?
(1) 22 m
(2) 12 m
(3) 5 m
var 17 m
A body starts with an initial velocity 10 m/s and
has a constant acceleration 2 m/s2 in the direction
of initial velocity. Its average velocity over an in-
terval of 10 seconds is
(1) 15 m/s
(2) 17.5 m/s
3.
131 20 m/s
(4)
22.5 m/s
need correct answers
u can copy from google
but I need correct explaination
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Answers
Answered by
3
Explanation:
1st-
S=ut+1/1at²
displacement in 3seconds.
S=12×3+1/2×2×3²
By same method find displacement in 2second
Displacement in 3rd second=displacement in 3 Seconds - displacement in 2 seconds
Solve yourself.
2nd
Average velocity=initial velocity+final
velocity/2
initial velocity=10m/s
V=u+at
so final velocity =30m/s
Now calculate yourself.
sonalkumarpathak8405:
in first answer is 17
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