A body moves along the curved path of a quarter circle.Calculate the ratio of distance to displacement
a) 11:7 b) 7:11 c)11:7√2 d) 7:11√2
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Given that the path is a quarter circle, the distance travelled = D = 1/4 x (2x pi (22/7) x R)
Formula for the circumference of circle being 2 x pi x r
Here the displacement length is the hypotenuse of an isosceles right angle triangle (two sides equal)
Pythagoras theorem will be applied (a2 +b2 =c2)
Displacement = d = √ [2(R^2)] = √ (2) x R
So ratio = D/d = [1/2 x √ (2)] x pi
Formula for the circumference of circle being 2 x pi x r
Here the displacement length is the hypotenuse of an isosceles right angle triangle (two sides equal)
Pythagoras theorem will be applied (a2 +b2 =c2)
Displacement = d = √ [2(R^2)] = √ (2) x R
So ratio = D/d = [1/2 x √ (2)] x pi
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Answer:
Given that the path is a quarter circle, the distance travelled = D = 1/4 x (2x pi (22/7) x R)
Formula for the circumference of circle being 2 x pi x r
Here the displacement length is the hypotenuse of an isosceles right angle triangle (two sides equal)
Pythagoras theorem will be applied (a2 +b2 =c2)
Displacement = d = √ [2(R^2)] = √ (2) x R
So ratio = D/d = [1/2 x √ (2)] x pi
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