Question

A body moves along the sides AB BC and CD of a square side 10m. with velocity of constant magnitude 3m/s Its average velocity will be​

Answer 1

A body moves along the sides AB BC and CD of a square side 10m. with velocity of constant magnitude 3m/s Its average velocity will be

Answer 2

Answer:

ItsSamGupta

• A body moves along the sides AB, BC and CD of a square of side 10 meter with velocity of constant magnitude 3 meter/sec.

T= 10/3

Now when particle moves from ab,bc,cd then it reaches to adjacent vertex D of square

Total time taken = 3t= 3(10/3)=10

Average velocity= total disp/ total time

= 10/10=1m/s