Question

A body moves from rest with a uniform acceleration and travel 270 m in 3 sec. Find the velocity of the body 10 sec after the start.

Answer 1

S = 270m
U=0 m/s
T= 3 s
S= ut +1/2at^2
270=0 + 1/2 a 9
A=60m/s^2
Now,
t=10s
S =ut+1/2at^2
S=0 + 1/2.60.100
So 's' or distance covered = 3000m or 3 km V=u + at V= 0+60.10=600m/s