a body moves from rest with a uniform acceleration and travels 270 m in 3s find the velocity of the body at 10s after the start
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First we will calculate acceleration.
We know
s = ut + 1/2 a. t2
or 270 = 0 . 3 + 1/2 . a. (3)2
Or a= (270 . 2) / 9
Or a= 60 m/s2
Again We know that:
a = (v - u ) / t
Or 60 = (v - 0 )/ 10
Or v = 60 . 10
∴ v = 600 m/sAnswer
This question like same to this answer
We know
s = ut + 1/2 a. t2
or 270 = 0 . 3 + 1/2 . a. (3)2
Or a= (270 . 2) / 9
Or a= 60 m/s2
Again We know that:
a = (v - u ) / t
Or 60 = (v - 0 )/ 10
Or v = 60 . 10
∴ v = 600 m/sAnswer
This question like same to this answer
vishalkk:
please mark as brilliant list
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