Question

a body moves from rest with uniform acceleration and travels 270m in 3s. find the velocity of the body 10 s after the start

Answer 1

#Finding acceleration
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s ( displacement)= 270 m
t ( time ) = 3s
u ( initial velocity) = 0 m/s [ as body starts from rest ]

using - s = ut+(½)at² ; where "a" is acceleration of the body ; we get ,

270 = (0)(3) +( ½)a(3)²
=> a = 60m/s²
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#Velocity of body after 10s
t ( time ) =10s
u ( initial velocity) = 0m/s
a ( acceleration) = 60m/s²

using : v = u + at ; where "v" is the velocity at time "t" ; we get ;

v = 0 + (60)(10) = 600 m/s .
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hope it helps !