Question

A body moves from rest with uniform acceleration and travels 250 m in 5 s. Find the velocity of the body at 10 s after the start. ​

Answer 1

S O L U T I O N :

$\underline\orange{\bf{Given\::}}$

Displacement, (S) = 250 m

Time taken, (t) = 5 sec.

Initial velocity, (u) = 0

$\underline\red{\bf{Explanation\::}}$

As we know that 2nd equation of motion;

$\boxed{\bf{S=ut + \frac{1}{2} at^{2}}}$

A/q

→ 250 = 0 × 5 + 1/2 × a × (5)²

→ 250 = 0 + 1/2 × a × 25

→ 250 = 0 + 25a/2

→ 250 = 25a/2

→ 500 = 25a

→ a = 500/25

→ a = 20 m/sec²

Now,

We will use the 1st equation of motion a/c to the given time;

Time, (t) = 10 sec.

$\boxed{\bf{v = u + at}}$

→ v = 0 + 20 × 10

→ v = 0 + 200

→ v = 200 m/sec.

Thus,

The final velocity of the body at 10 sec after start will be 200 m/sec.

Answer 2

Explanation:

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