if a+b+c=7and ab+bc+ca=20,find the value of a^2+b^2+c^2
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Answered by
2
Answer:
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Using
(a+b+c)² formula
(a+b+c)²=a²+b²+c²+2ab+2bc+2ac
(a+b+c)²-2ab-2bc-2ac=a²+b²+c²
(7)²-2(ab+bc+ac)=a²+b²+c²
49-2(20)=a²+b²+c²
therefore, a²+b²+c²=9
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Answered by
0
Answer:
(a+b+c)2= a2+b2+c2+2(ab+bc+ca)
72 = a2+b2+c2+ 2×20
49 = a2+b2+c2 + 40
49 - 40 = a2+b2+c2
.·. 9 = a2+b2+c2
Ans : 9
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