A body moves from rest with uniform acceleration and travels 270m in 3 sec .Find the velocity of the body at 10 sec from the start
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Hey mate !
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Given :
Initial velocity (u) = 0 m/s.
Distance (s) = 270 m.
Time (t) = 3 secs.
To find :
Acceleration (a) =?
Velocity after 10 sec.
Solution :
We will use third equation of motion here;
s = ut + 1 / 2 at²
⇒ 270 = 0 * 3 + 1 / 2 * a * 3 * 3
⇒ 270 = 9 / 2 a
⇒ 9a = 540
⇒ a = 540 / 9
⇒ a = 60 m/s²
Now,
We will use first equation of motion here ;
After 10 secs.
v = u + at
⇒ v = 0 + 60 * 10
⇒ v = 600
⇒ v = 600 m/s.
Hence,
The final velocity acquired by the car is 600m/s.
______________________
Thanks for the question !
☺️☺️☺️
_______________________
Given :
Initial velocity (u) = 0 m/s.
Distance (s) = 270 m.
Time (t) = 3 secs.
To find :
Acceleration (a) =?
Velocity after 10 sec.
Solution :
We will use third equation of motion here;
s = ut + 1 / 2 at²
⇒ 270 = 0 * 3 + 1 / 2 * a * 3 * 3
⇒ 270 = 9 / 2 a
⇒ 9a = 540
⇒ a = 540 / 9
⇒ a = 60 m/s²
Now,
We will use first equation of motion here ;
After 10 secs.
v = u + at
⇒ v = 0 + 60 * 10
⇒ v = 600
⇒ v = 600 m/s.
Hence,
The final velocity acquired by the car is 600m/s.
______________________
Thanks for the question !
☺️☺️☺️
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