Question

a body moves in a straight line along x axis it distance from the origin is given by equation x=8t-3t^2 where x is in second find displacement of particle when it's velocity is zero

Answer 1

a body moves in a straight line along x axis it distance from the origin is given by equation x=8t-3t^2 where x is in second find displacement of particle when it's velocity is zero

answer : 16/3 m

solution : velocity is the rate of change of displacement with respect to time.

i.e., v = dx/dt

so, after differentiating x with respect to time , we get velocity - time function.

i.e., v = d(8t - 3t²)/dt = 8 - 6t

hence, v = 8 - 6t

a/c to question, we have to find displacement when velocity becomes zero.

so, v = 8 - 6t = 0 => t = 4/3 s

now putting t = 4/3s in equation, x = 8t - 3t²

so, displacement of particle , x = 8(4/3) - 3(4/3)² = 32/3 - 16/3 = 16/3 m

Answer 2

Explanation:

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