Question

A body moves in a straight line along x-direction for which graph of v vs x is shown in the gray magnitude of acceleration of the body at x = 3m?


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Answer 1

Answer:

| a | = 2

Explanation:

Using the equation of motion: (v^2 = u^2 + 2as)

Final velocity at 3m, v = 2 m/s

Initial velocity of the body, u = 4 m/s

Displacement, s = 3m

Applying the equation,

2^2 = 4^2 + (2x3)a

4 = 16 + 6a

4-16 = 6a

-12 = 6a

-2 = a

Therefore, a = -2 m/s^2 and it's magnitude = 2 (sign removed in magnitude).



Answer 2

Answer:

The magnitude of acceleration is $2m/s^{2}$.

Explanation:

The equations of motion will be used her.

Acceleration is defined as the rate of change of velocity.

If velocity is constant, the acceleration produced is zero.

Third equation of motion is

$v^2 = u^2 + 2as$

$s=3m$

From graph,

$v=2m/s$

Initial velocity is $u=4m/s$

Using values,

$2^2 = 4^2 + (2x3)a$

$4 = 16 + 6a$

$-12 = 6a$

$-2 = a$

Ignoring negative sign as we need magnitude only.

$a=2m/s^{2}$

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