Physics, asked by nehaixsharma19pda5s1, 1 year ago

a body moves in a straight line and covers first half the distance with speed 5 metre per second and second half into equal halfs with speed 4 metre per second and 3meter per second respectively . the average velocity of the body is

Answers

Answered by ShuchiRecites
5
\textbf{ Hello Mate }

Let the total distance b x

First half distance will be x / 2

Speed = Distance / Time

5 m/s= ( x / 2 ) / t1

t1 = x / 10

Now, what is remaining distance?

x - x / 2 = x / 2 is remaining distance out of which is equally divided into two halves

So those to halfs wil be x / 2 × 1 / 2 = x / 4

Now, body covered

4 m/s = ( x / 4 ) / t2

t2 = x / 16

3 m/s = ( x / 4 ) / t3

t3 = x / 12

Average speed = Total distance / total time

= x / ( x / 10 + x / 16 + x / 12 )

= x / ( 24x + 15x + 20x ) / 240

= ( x / 59x ) × 240

= 4.1 m/s

Have great future ahead!
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