Question

A body moves in a straight line with uniform acceleration of 2 m/s2. If the initial
velocity of the body is 16 m/s, find its final velocity after covering 36 m of
distance using the third equation of motion.
O a) v = 10 m/s
Ob) v = 15 m/s
O c) v = 6 m/s
O d) v = 20 m/s​

Answer 1

The answer is d v = 20 m/s

hope it will be helpful to you

Answer 2

Answer:

v =20

Explanation:

Here we have

acceleration =2m/s^2. (please note that' ^ 'refers to the power)

initial velocity=16m/s

distance =36m

using

v^2=u^2+2as

where v =final velocity

u =initial velocity

a = acceleration

s = distance (or displacement)

v^2 = (16)^2 +(2)(2)(36)

$v = \sqrt{(256) + (144)}$

$v = \sqrt{400}$

$v = 20$

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