Question

A body moves on a circular track of radius R. It starts from a point on circular path and goes through one sixth-part of the circumference of the circular path. The magnitude of displacement of the body is.​

Answer 1

Answer:

What is the government formed by an alliance of two or more political parties called

Answer 2

The displacement of the body is 9.42R.

Given,

A circular path or radius=R

The body moves through one sixth-part of the circumference of the circular path.

To find,

the magnitude of displacement of the body.

Solution:

• Displacement is the change in position of an object.
• It  is the direct length between any two points when measured along the minimum path between them.
• It is a vector quantity and has a direction and magnitude.
• Displacement can be positive, negative or zero.

As the body moves on a circular path, the complete distance will be taken as the circumference of the circle i.e 2πR where, R is the radius of the earth.

As given above that the body only covers one-sixth part of the circumference of the circular path, its displacement will also be the  covers one-sixth part of the circumference,

Displacement of the body will be,

$=\frac{1}{6} X2\pi XR\\=\frac{1}{6} X2X3.14XR\\=3X3.14XR\\=9.42R.$

Hence, the displacement is 9.42R.

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