Question

A body moves over a horizontal surface with an initial velocity of 2 m/s. Due to friction, its velocity decreases uniformly at the rate of 0.25 m/s2. How much time will it take to stop?

Answer 1

so, your answer is 8 sec sec

sorry answer is mistaken in image

a=v-u/t

-.25= 0-2/t

t=-2/-.25

t=8 sec.

hope you are satisfied with my answer

Answer 2

!! Hey Mate !!

your answer is --

Given, A body moves over a horizontal surface with an initial velocity of 2 m/s. Due to friction, its velocity decreases uniformly at the rate of 0.25 m/s2.

such that, it's initial velocity u = 2m/s,

acceleration a = -0.25m/s^2 and it's final

velocity v = 0 .


Now, according to formula

✔✔ v = u + at

=> 0 = 2 - 0.25t

=> -2 = -0.25t

=> t = 2/0.25

=> t = 8 second



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