Question

a body moves over horizontal surface with an initial velocity of 2m/s due to friction its velocity decreases uniformly at the rate of 0.75m/s^2 how much time will it take to stop​

Answer 1

Answer:

u=2

a=0.75

v=0

a=v-u/t

t=-2/0.75 seconds

Answer 2

Answer:

U = 2m/s

V = 0m/s

a = 0.75m/s

We know that :

v = u +ut

then

t = v - u/a

= 0 - 2 / 0.75

= - 200 / 75

= - 2.67 sec.