Question

a body moves towards east by a distance of 3km and turn towards north and moves a distance of 4km .what is the magnitude of displacement of the body?

Answer 1

see it moves towards east 3 km then turns north 4 km means if we draw a diagram it will be triangle and by pythagoras theorem 
                     [hypo.]²=[1 side]²+[2 side]²
                               =3^2+4^2
                              =9+16
                      5^2        =25
i.e. displacement = 5 km

                       

Answer 2

Answer:

The magnitude of displacement of the body is 5km.

Explanation:

Let's say the body starts from the point O and reaches A after moving 3km toward the east. Further, it reaches point B after moving 4km toward north.

Tracing the path of the body gives us a right-angled triangle with :

$perpendicular = 4km$

$base=3km$

and the hypotenuse is the minimum distance between the initial and final point i.e. the displacement of the body.

Now, Using Pythagoras theorem:

$(hypotenuse)^2=(perpendicular)^2+(base)^2$

$\therefore (displacement)^2=3^2+4^2$

$\implies displacement = \sqrt {9+16} = \sqrt {25}$

$\implies displacement = 5km$

$\therefore$ The magnitude of displacement of the body is 5km.

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