Question

A body moves with a uniform velocity of 4m/s starting it's journey t=0. Another body starting from rest moves with acceleration 1m/s from the same point at t=0. When and where the two bodies will meet ?​

Answer 1

Answer:

Explanation:

Distance covered by body 1 in time t is =4m/s*t

Distance covered by body 2 in time t is =1/2*1m/s²*t² (by second formula of motion)

When they meet distance covered and time taken will be same for both of them hence

4m/s*t=1/2*1m/s²*t²

8s=t