a body moves with a uniform velocity of 5m/s from a point. From the same point at the same time another body starts from rest and moves with uniform acceleration 2ms-2 in the same direction. When and where do they meet?
Answers
let the two bodies meet after time "t"
consider the motion of first body
X₁ = distance traveled by the first body
v₁ = velocity of the first body = 5 m/s
t = time of travel
distance traveled by the first body is given as
X₁ = v₁ t
X₁ = 5 t eq-1
consider the motion of second body
X₂ = distance traveled by the first body
v₂ = velocity of the second body = 0 m/s
a = acceleration of the second body = 2 m/s²
t = time of travel
distance traveled by the second body is given as
X₂ = v₂ t + (0.5) a t²
X₂ = 0 t + (0.5) (2) t²
X₂ = t² eq-2
for the two bodies to meet
X₁ = X₂
5t = t²
t = 5 sec
so they meet after 5 sec
using eq-1
X₁ = 5 t
X₁ = 5 x 5 = 25 m
they meet after travelling 25 m