Question

a body moves with initial velocity of 5 M per second and uniform acceleration of 0.4m / second calculate the velocity after 12s and distance travelled in this time

Answer 1

velocity=9.8 m/s
distance=88.8 m
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Answer 2

Answer:

answer are :-.

Explanation:

GIVEN

INITIAL VELOCITY (u). 5M/S

ACCELERATION (a). 0.4M/S²

TIME (t). 12 SEC

FINAL VELOCITY. = ???

SOLUTIONS:-.

V = u+at

=. 5+0.4x 12

= 5+4.8

= 9.8m/s

second equation.

s = ut + 1/2at²

= 5x12+1/2x0.4x(12)²

= 60+ 1/2x0.4x144

= 60+0.4x72

= 60+28.8

= 88.8

SO, DISTANCE IS 88.8 (ANSWER).

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