a body moves with velocity 4m/sec north for 3 secs. it turns right and moves with velocity 3m/sec for 2 secs. find average speed
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Let the first velocity be v1=4m/s
and the second be v2=3m/s
It goes at velocity v1 for 3 s.
So the distance covered will be v1×3s
=4m/s×3m =12m
and it goes with velocity v2 for 2 s
so the distance will be
=v2×2s = 3m/s×2s =6m
so the total distance is 18 m
And the total time is (3+2)s =5s.
So the avg. speed will be =18/5 m/s
3.6m/s.
Hope it helped.
and the second be v2=3m/s
It goes at velocity v1 for 3 s.
So the distance covered will be v1×3s
=4m/s×3m =12m
and it goes with velocity v2 for 2 s
so the distance will be
=v2×2s = 3m/s×2s =6m
so the total distance is 18 m
And the total time is (3+2)s =5s.
So the avg. speed will be =18/5 m/s
3.6m/s.
Hope it helped.
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