Question

A body moving along a straight line at 40 m/s undergoes an acceleration of 4 m/s2. after 10 seconds its speed will be

Answer 1

initial speed (u)=40 m/s
final speed(v) =v
a=4m/s2
t=10sec
as we know:
         v=u+at
         v=4*10+40
          v=40+40
          v=80m/s

Answer 2

Answer:

Concept:

The rate at which an object's velocity with respect to time changes is known as acceleration in mechanics. The vector quantity of accelerations (in that they have magnitude and direction). The direction of the net force on the object determines the direction of its acceleration. the amount of acceleration that an object experiences, as per Newton's Second Law.

Given:

A body travelling in a straight line at 40 m/s experiences a 4 m/s2 acceleration. Its velocity will be after 10 seconds

Find:

find after 10 seconds its speed will be

Answer:

When a particle is travelling uniformly in a circle at a constant speed, the velocity vector's direction changes, causing an acceleration, but the particle's acceleration itself doesn't change. The formula is a = v/t = (vf-vi)/. (tf - ti). After subtracting the initial speed from the final velocity, multiply the result by the time interval. Your average acceleration throughout that period is the end result.

initial speed (u)$=40 m/s$

final speed(v) =v

$a=4m/s^{2}$

$t=10sec$

as we know:

$v=u+at\\ v=4*10+40\\ v=40+40\\v=80m/s$

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