Question

a body moving along straight line such that its velocity represented through X and velocity gradient is represented through y then relation between X and y for moment under constant acceleration may be​

Answer 1

Given:

A body moving along straight line such that its velocity represented through X and velocity gradient is represented through Y.

To find:

Relation between X and Y for constant acceleration?

Calculation:

As per question:

• v = X
• dv/ds = gradient = Y

Let acceleration be constant and equal to k:

$\therefore \: a = k$

$\implies \: \dfrac{dv}{dt} = k$

Now, applying Chain Rule of Differentiation:

$\implies \: \dfrac{dv}{ds} \times \dfrac{ds}{dt} = k$

$\implies \: \dfrac{dv}{ds} \times v = k$

$\implies \: Y\times X = k$

$\implies \: XY = k$

So, final answer is:

$\boxed{\bf XY = k}$

Answer 2

Explanation:

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