Question

A body moving along x -axis is at x=+1m at t=0 and x=+5 at t=1s and move to x=-3 at t=2s then its average velocity in first 2s in ms^(-1) is 1) +4 2) -2 3) -4 4) +2

Answer 1

Answer:

- 2m/s

Explanation:

Velocity is independent of the path, it just depends on the initial and final position(vector).

Initially, at t = 0, x = + 1m (x-axis)

Finally, at t = 2, x = - 3m (x-axis)

Displacement = final - initial position

Displacement = -3 - (+1) = - 4m (x-axis)

Time taken = 2 - 0 = 2s

Therefore, velocity is :

= displacement/time

= -4/2 m/s

= - 2 m/s (along x-axis)

Average velocity is - 2m/s.

Answer 2

Answer:

The answer is option [2]. $-2m/s$

Explanation:

A vector quantity is average velocity. The positional shift or displaced (∆x) multiplied by the time intervals (∆t) during which the displacement happens is the definition of average velocity. Based on the direction of the movement, the average velocity might either be negative or positive. The average velocity is measured in metres per second, or M/s.

The initial and terminal positions are the only factors that determine velocity, not the journey (vector).

Initially, at $t=0,$

                 $x = + 1m$

Finally, at

                  $t=2,$

                  $x = - 3m$

$Displacement = final position - initial position$

$Displacement = -3 - (+1)$

                       $= - 4m$

$Time taken = 2 - 0$

                  $= 2s$

Consequently, velocity is

                                  $=\frac{displacement}{time}$

                                   $=\frac{-4}{2} m/s$

                                    $= - 2 m/s$

Average velocity is $- 2m/s$

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