a body moving along x direction has x co ordinate any constant is given by x=A+BT+CT^2 what is its acceleration?
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3
double differentiate it wrt time
as dx/dt = v
and dv/dt = a
dx/dt = B + CT { power rule : whatever the variable , that's power comes down by one and the previous power is multiplied to that term
a = dv/dt = C
as dx/dt = v
and dv/dt = a
dx/dt = B + CT { power rule : whatever the variable , that's power comes down by one and the previous power is multiplied to that term
a = dv/dt = C
Answered by
2
Answer:
2c m/s2
Explanation:
so s(displacement)=a+bt+ct2
we do d/dx(a+bt+ct2) and also a, b, c are constants
=0+b+2ct
=b+2ct m/s =velocity
to get acceleration we must further differentiate b+2ct
=d/dx(b+2ct)
=0+2c
=2c m/s2
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