Question

A body moving from rest with uniform acceleration travels a distance X in the first t seconds and travels a distance Y with same acceleration in the next 2t seconds, then
(A) y=4x
(B) y=(1/2)x
(C) y=2x
(D) y=3x

Kindly Explain The Answer If Not Answer Correctly I will report Him/Her.

Answer 1

Answer:

Correct relationship is Y = 3X

[Option.B]

Explanation:

We have:

→ Initial velocity (u) = 0

→ Distance in first 't' seconds = X → Distance in next '2t' seconds = Y

→ Acceleration is same.

1 case .

By the 2nd equation of motion :

s = ut + 1at²

→ X = 0(t) + 1/2 ×a×t²

⇒ X = 1at²

→ X = 0.5at²

•

2 case.

Distance travelled by the body in next '2t' seconds will be:

Y = [0(t) + 12×a × (2t)²] -0.5t²

→ Y = [2 × a × 4t²] -0.5at²

→ Y = 2at² - 0.5at²

→ Y = 1.5at²

On dividing eq. 2 by eq.1 we get :

Y/X = 1.5at²/0.5at²

→ Y/X = 3

→ Y= 3x