Question

a body moving velocity 40m/s brought
to rest with in 5s. find dist
ance travelled by it before it comes to rest​

Answer 1

Answer:

If initial velocity be u and the acceleration be a then the distance in first 5s will be S

5

=u(5)+

2

a(5)

2

=40m........(1)

and the distance in first 10s will be S

10

=u(10)+

2

a(10)

2

so the distance between time t=5s to t=10 will be

S

5

′

=S

10

−S

5

=65m ...........(2)

putting corresponding values and solving the equation-1 and equation-2 we get u=5.5m/s

Option C is correct.