A body moving with 10m/s comes to rest in 2sec. Find retardation
Answers
Answered by
6
u=10m/s
v=0
t=2sec
a=?
We can use the first equation of motion
v=u+at
a= (v-u)/t
a= -10/2
a= -5m/s^2
So retardation is 5m/s^2
v=0
t=2sec
a=?
We can use the first equation of motion
v=u+at
a= (v-u)/t
a= -10/2
a= -5m/s^2
So retardation is 5m/s^2
Similar questions