A body moving with a certain velocity is brought to rest in 8 seconds. Calculate its initial velocity if the body was decelerated by 2 m/s^2.
Answers
Answered by
5
Final velocity =0
Time taken =8s
Acceleration = -2m/s^2
Let initial velocity be u
Using acceleration formula
a=(v-u)/t
-2 = (0-u)/8
-16 = -u
u= 16
So, the inital velocity was 16m/s
Time taken =8s
Acceleration = -2m/s^2
Let initial velocity be u
Using acceleration formula
a=(v-u)/t
-2 = (0-u)/8
-16 = -u
u= 16
So, the inital velocity was 16m/s
Saanvipriya:
thank you sooooo much
Answered by
3
v=0
u =?
t= 8sec
a = - 2 m/s²
o = u - 2 x 8
u = 16 m/s
u =?
t= 8sec
a = - 2 m/s²
o = u - 2 x 8
u = 16 m/s
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