Question

A body moving with a constant acceleration
travels the distances 3 m and 8 m respectively in
I s and 2 s. Calculate : (i) the initial velocity, and
(ii) the acceleration of body.
Ans. (1) 2 ms-1 GH)2 m2​

Answer 1

Case 1:

We know

s = ut + 1/2 a. t2

Or s1 = ut1 + 1/2 a. t12

or 3 = u . 1 + 1/2 .a . 12

or 3 = u + a/2 -------Eqn. 1

Case 2:

s2 = ut2 + 1/2 a. t22

or 8 = u . 2 + 1/2 .a . 22

or 8 = 2u + 2a

or 8/2 = (2u + 2a)/2

or 4 = u + a -------Eqn. 2

Subracting Eqn. 1 from Eqn. 2 (Eqn. 2 - Eqn. 1) We have:

4 - 3 = (u + a) - (u + a/2)

Or 1 = u + a - u - a/2

Or 1 = a - a/2

Or 1 = (2a - a)/2

Or 1 = a /2

Or a = 2 m/s2

Putting the value of a in Eqn. 1 we have:

3 = u + 2/2

3 = u + 1

Or u = 3 - 1

Or u = 2 m/s

∴ Initial velocity (u)= 2 m/s

Acceleration (a) = 2 m/s2

$ItzDopeGirl$❣

Answer 2

Answer:We know

s = ut + 1/2 a. t2

Or s1 = ut1 + 1/2 a. t12

or 3 = u . 1 + 1/2 .a . 12

or 3 = u + a/2 -------Eqn. 1

Case 2:

s2 = ut2 + 1/2 a. t22

or 8 = u . 2 + 1/2 .a . 22

or 8 = 2u + 2a

or 8/2 = (2u + 2a)/2

or 4 = u + a -------Eqn. 2

Subracting Eqn. 1 from Eqn. 2 (Eqn. 2 - Eqn. 1) We have:

4 - 3 = (u + a) - (u + a/2)

Or 1 = u + a - u - a/2

Or 1 = a - a/2

Or 1 = (2a - a)/2

Or 1 = a /2

Or a = 2 m/s2

Putting the value of a in Eqn. 1 we have:

3 = u + 2/2

3 = u + 1

Or u = 3 - 1

Or u = 2 m/s

∴ Initial velocity (u)= 2 m/s

Acceleration (a) = 2 m/s2