A body moving with a constant acceleration Travels the distance 3 m and 8 M respectively in 1 seconds and 2 seconds calculate the initial velocity and the acceleration of the body
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d_{1} = 3 m
t_{1} = 1 sec
d_{2} = 8 m
t_{2} = 2 sec
s = ut + \frac{1}{2} at^{2}
For s = 3 and t = 1
3 = u * 1 + \frac{1}{2} at^{2} (i)
For s = 8 and t = 2
8 = 2 * u + 0.5 * a * 4 (ii)
Solving i and ii we get u = 2 m/s and a = 2m/s^{2}
t_{1} = 1 sec
d_{2} = 8 m
t_{2} = 2 sec
s = ut + \frac{1}{2} at^{2}
For s = 3 and t = 1
3 = u * 1 + \frac{1}{2} at^{2} (i)
For s = 8 and t = 2
8 = 2 * u + 0.5 * a * 4 (ii)
Solving i and ii we get u = 2 m/s and a = 2m/s^{2}
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