Question

A body moving with a uniform acceleration crosses a
distance of 65 m in the 5 th second and 105 m in 9th second.
How far will it go in 20 s?

(a) 2040m (b) 240m (c) 2400m (d) 2004m​

Answer 1

Answer:

2400

Explanation:

65=u+a(9/2)

105=u+a(17/2)

by solving above equations we get

u=20m/s,a=10m/s^2

substitute these values in the equation

s=ut+1/2at^2 where t=20sec

s=400+2000=2400

Answer 2

Explanation:

65=u+a(9/2)

105=u+a(17/2)

by solving above equations we get

u=20m/s,a=10m/s^2

substitute these values in the equation

s=ut+1/2at^2 where t=20sec

s=400+2000=2400

Hope it helps :)