Question

In figure,BE=DC and angle BEC=angle CDB=90 degree. Can you prove triangle BEC=triangle CDB? If yes , which congruence criteria will you follow?

Answer 1

Answer:

In △ABD and △CDB

AB=CD (given)

∠ABD=∠CDB (given)

BD=DB (common side)

∴△ADB≅△CDB by SAS criteria.

So option A is correct.