A body moving with a uniform acceleration describes 12 m in third second of its motion and 20 m in the fifth second. find its velocity after 10 second.
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velocity at 7th and 9th second be v7 and v9.
V7= 20 m/s and V9= 24 m/s
Rate of change of velocity=(V9-V7) / Change in time
This implies Uniform acceleration = (24–20)/2
Thus acceleration a=2 m/s2
Now, distance travelled in 15th second is Veloctiy at t=15 s. Let's call it V15;
According the well known formula:
V15= U7 + a*time = 20+(2*8) = 36 m/s
Thus the body will travel 36m in the 15th second.
Do post comments in case you need clarifications!
V7= 20 m/s and V9= 24 m/s
Rate of change of velocity=(V9-V7) / Change in time
This implies Uniform acceleration = (24–20)/2
Thus acceleration a=2 m/s2
Now, distance travelled in 15th second is Veloctiy at t=15 s. Let's call it V15;
According the well known formula:
V15= U7 + a*time = 20+(2*8) = 36 m/s
Thus the body will travel 36m in the 15th second.
Do post comments in case you need clarifications!
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