a body moving with a uniform retardation the equationv of motion v=?
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Explanation:
let us suppose that its initial velocity = u
using equation of motion
v2=u2+2as
(u/2)2 = u2 =2*a*3000 (value of final velocity is haif he initial taht is u/2 and s = 3 km =3000m)
 (u2/4) – u2 =2*a*3000
 (-3u2/4)=2*a*3000
 – u2=(2*a*3000*4)/3
 u2 = – 8000*a ….............................1
by appling the same equation when it comes to rest we get
02=(u/2)2 +2*a*s
 – u2/4 =2*a*s
 – u2/(4*2*a) = s
 – u2/8a = s
after substituting values form 1 we get
 – (-8000*a)/8a = s
 s = 1000m = 1km
Hope it helps.........
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