Question

A body moving with a velocity o 2 m s-1 acquires and velocity of 10 m s-1 in 5 s. Find its acceleration.

Answer 1

u=2m/s
v=10m/s
t=5s
a=(v-u)/t
  =(10-2)/5
   =1.6m/s^2

Answer 2

"The acceleration of the moving ball is $1.6\quad \frac { m }{ s^{ 2 } }$

Given:

"Initial velocity" = u = 2 m/s

"Final velocity" = v = 10 m/s

Time = t = 5 sec

Solution:

We know that,

Acceleration is rate of change of velocity. It is also difference between final velocity and initial velocity with "respect to time".

Then its acceleration 'a' is given by

$a\quad =\quad \frac { v\quad -\quad u }{ t }$

$a\quad =\quad \frac { 10\quad -\quad 2 }{ 5 }$

$a\quad =\quad 1.6\quad \frac { m }{ s^{ 2 } }$"