A body moving with a velocity of 20 m/s is brought to rest with uniform retardation in 4 second. Calculate the retardation and the distance travelled by the body before coming to rest.
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Answer:
retardation is -5m/S2 and distance is 40meters
Explanation:
v=u+at
0=20+a(4)
a= -5m/s2
v2-u2=2as
0-400=2(-5)s
s=40m
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