A body moving with a velocity of 6 m/s uniformly accelerates at 1.5 m/s2. What will be iys velocity after 5 seconds and how far will it move during this time?
Answers
u=6 m/s
t=5s
a=1.5 m/s^2
v=?
v=u+at
v=6+7.5=13.5 m/s
Now,s=ut+1/2at^2
s=30+3.75
s=33.75 m/s.
The velocity of the body after 5 seconds is 13.5 m/s.
The distance covered during this time is 48.75 m.
Given: A body moving with a velocity of 6 m/s uniformly accelerates at 1.5 m/s² for 5 seconds.
To Find: The velocity of the body after 5 seconds and the distance covered during this time.
Solution:
We can solve the numerical by applying the formulas of motion given by;
v = u + at ...(1)
S = ut + 1/2 at² ...(2)
Where v = final velocity, u = initial velocity, a = acceleration, S = distance.
Coming to the numerical, we have;
The initial velocity (u) = 6 m/s
The acceleration of the body (a) = 1.5 m/s²
The time duration = 5 sec
Putting the respective values in (1), we get;
v = u + at
⇒ v = 6 + ( 1.5 × 5 )
⇒ v = 6 + 7.5
= 13.5 m/s
So, the final velocity of the body is 13.5 m/s.
Now, for distance covered, we need to put respective values in (2),
S = ut + 1/2 at²
⇒ S = ( 6 × 5 ) + ( 1/2 ) × 1.5 × 5²
⇒ S = 30 + 18.75
⇒ S = 48.75 m
So, the distance covered is 48.75 m.
Hence, the velocity of the body after 5 seconds is 13.5 m/s.
The distance covered during this time is 48.75 m.
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